Home › Maharashtra HSC Class 12 (Science) › physics › Oscillations › A particle of mass 0.2 kg performs S.H.M. of amp…
A particle of mass 0.2 kg performs S.H.M. of amplitude 0.05 m with period π s. Its maximum kinetic energy (in mJ) is approximately
A5
B25
C1
D10
Answer & Solution
Correct answer: D. 10
1. ω = 2π/T = 2 rad/s.
2. Maximum speed v_max = ωA = 2 × 0.05 = 0.1 m/s.
3. KE_max = ½ m v_max² = ½ × 0.2 × 0.01 = 0.001 J.
4. Converted to mJ this is 1 mJ; the closest option is 1.
_Source: Maharashtra Balbharati Std XII Physics, Ch 5 "Oscillations" §5.6_
Related questions
In damped harmonic motion, the amplitude of oscillationTwo springs of force constants k₁ and k₂ are connected in series and stretched by an exterA particle in S.H.M. of period 2 s starts from rest at the extreme position. Its displacemThe kinetic energy of a particle of mass m in linear S.H.M. of amplitude A at displacementA simple pendulum of length 1 m on the earth's surface (g = π² m/s²) has periodA spring-mass system of mass m and spring constant k oscillates with periodA particle executes S.H.M. with amplitude A and angular frequency ω. Its maximum acceleratWhich of the following is a periodic but NOT oscillatory motion?