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A particle in S.H.M. of period 2 s starts from rest at the extreme position. Its displacement at t = 0.5 s as a fraction of amplitude is
A0
B1
C1/√2
D1/2
Answer & Solution
Correct answer: A. 0
1. Starting from rest at extreme position: x(t) = A cos(ωt) with ω = 2π/T = π rad/s.
2. At t = 0.5 s: x = A cos(π × 0.5) = A cos(π/2).
3. cos(π/2) = 0, so x = 0 (passing through mean position).
_Source: Maharashtra Balbharati Std XII Physics, Ch 5 "Oscillations" §5.3_
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