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The kinetic energy of a particle of mass m in linear S.H.M. of amplitude A at displacement x is
A½ mω²(A² + x²)
B½ mω² x²
C½ mω² A²
D½ mω²(A² − x²)
Answer & Solution
Correct answer: D. ½ mω²(A² − x²)
1. For S.H.M., velocity v = ω √(A² − x²).
2. Kinetic energy KE = ½ m v² = ½ m ω² (A² − x²).
3. It is maximum at x = 0 and zero at x = ±A.
_Source: Maharashtra Balbharati Std XII Physics, Ch 5 "Oscillations" §5.6_
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