A pendulum bob oscillates as $x(t) = 0.05\cos(2\pi t)$ in metres. Its amplitude and period are:
A$0.05$ m and $\pi$ s, with frequency 1 Hz
B$2\pi$ m and $0.05$ s, the inverted ratio result
C$0.05$ m and $1$ s, since $\omega = 2\pi$ gives $T = 1$
D$0.10$ m and $2$ s, doubling both amplitude and period
Answer & Solution
Correct answer: C. $0.05$ m and $1$ s, since $\omega = 2\pi$ gives $T = 1$
$A = 0.05$ m, $\omega = 2\pi \Rightarrow T = 2\pi/\omega = 1$ s.
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