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A car decelerates from $20$ m/s to rest in $50$ m. Its acceleration magnitude is:
A$2$ m/s$^2$, taking the stopping time to be exactly 10 s
B$8$ m/s$^2$, twice the simple time-based estimate value
C$4$ m/s$^2$, since $v^2 = u^2 + 2as$ gives $a = 4$
D$10$ m/s$^2$, equal to gravitational acceleration $g$
Answer & Solution
Correct answer: C. $4$ m/s$^2$, since $v^2 = u^2 + 2as$ gives $a = 4$
$0 = 20^2 - 2a\cdot 50 \Rightarrow a = 4$ m/s$^2$.
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