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A jogger runs $300$ m east on the park track in $50$ s, then immediately $200$ m west in $50$ s. The average velocity over the full trip is:
A$5$ m/s east, equal to the average speed of the run
B$1$ m/s east, since net displacement is $100$ m in $100$ s
C$0$ m/s, since the jogger keeps changing direction
D$2.5$ m/s east, the mean of the two leg speeds
Answer & Solution
Correct answer: B. $1$ m/s east, since net displacement is $100$ m in $100$ s
Net displacement $= 300 - 200 = 100$ m east; total time $100$ s; average velocity $1$ m/s east.
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