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A father is 30 years older than his son. After 5 years the father will be three times as old as the son. Find their present ages.
AFather 50, Son 20
BFather 35, Son 5
CFather 40, Son 10
DFather 45, Son 15
Answer & Solution
Correct answer: C. Father 40, Son 10
Let son = y, father = y + 30. After 5: y + 35 = 3(y + 5) ⇒ y + 35 = 3y + 15 ⇒ 2y = 20 ⇒ y = 10. Father = 40.
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