A solenoid’s turns are doubled and its current halved. Its length and core are unchanged. How does its magnetic-field strength change?
AIt halves
BIt remains unchanged
CIt becomes four times as large
DIt doubles
Answer & Solution
Correct answer: B. It remains unchanged
For unchanged geometry and core, field strength is proportional to turns times current, so doubling turns and halving current cancel.
Keep practising General Science and Everyday Applications
Browse all General Science and Everyday Applications questions for RPF Constable, or explore more General Awareness topics.
Related questions
Everyday science resultsA lamp rated 100 W at 200 V runs at 100 V for 5 h. Assume constant resistance. At ₹8 per kTwo 12 Ω resistors run across 12 V: first in series for 1 min, then in parallel for 1 min.A 4 Ω resistor is in series with a parallel pair of 6 Ω and 3 Ω across 12 V. Find total cuBulbs rated 60 W and 40 W at 200 V are connected in series across 200 V. Assume constant rResistors of 6 Ω and 3 Ω are in parallel across an ideal 6 V battery. What are the total cA child stands 1.5 m from a plane mirror, then moves 0.5 m towards it. What is the new chiMatch heat transfer: along a metal spoon; circulating water; sunlight through space.