alleryTwo 12 Ω resistors run across 12 V: first in series for 1 min, then in parallel for 1 min. What total energy is used?
A1800 J
B1080 J
C720 J
D1440 J
Answer & Solution
Correct answer: A. 1800 J
The series stage uses (12²/24) × 60 = 360 J and the parallel stage uses (12²/6) × 60 = 1440 J, totalling 1800 J.
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