Which of the following is the correct **decreasing order** of standard reduction potential (i.e. from strongest oxidising agent to weakest)?
ALi⁺ > Na⁺ > Zn²⁺ > Cu²⁺ > F₂
BF₂ > Cu²⁺ > Zn²⁺ > Na⁺ > Li⁺
CCu²⁺ > F₂ > Li⁺ > Zn²⁺ > Na⁺
DNa⁺ > Zn²⁺ > Cu²⁺ > Li⁺ > F₂
Answer & Solution
Correct answer: B. F₂ > Cu²⁺ > Zn²⁺ > Na⁺ > Li⁺
Highest E°(reduction) ⇒ strongest oxidising agent. F₂/F⁻ ≈ +2.87 V (highest); Cu²⁺/Cu ≈ +0.34 V; Zn²⁺/Zn ≈ −0.76 V; Na⁺/Na ≈ −2.71 V; Li⁺/Li ≈ −3.04 V (lowest, weakest oxidising agent — but Li metal is the strongest reducing agent).
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