The product of any three consecutive positive integers is always divisible by

B12

Answer & Solution

Correct answer: D. 6

Among any three consecutive integers, at least one is divisible by 2 and exactly one is divisible by 3. Hence the product is divisible by $2 \times 3 = 6$. It need not be divisible by 4 (e.g. $1\cdot2\cdot3 = 6$).

Practise this question with Quill — AP Calculus AB →

Keep practising Unit 1B3: Asymptotic Behavior and Infinite Limits

Browse all Unit 1B3: Asymptotic Behavior and Infinite Limits questions for AP Calculus AB, or explore more Mathematics topics.

Start a Unit 1B3: Asymptotic Behavior and Infinite Limits lesson →

Related questions

In a parallelogram HELP with diagonals intersecting at O: OE = 4 cm and the diagonal HL = The diagonals of a quadrilateral are PERPENDICULAR BISECTORS of each other but they are NO The diagonals of a RHOMBUS are:In a parallelogram, two adjacent angles are in the ratio 3 : 2. The four angles of the par In parallelogram PQRS, PQ = 12 cm and QR = 7 cm. The perimeter of PQRS is:The diagonals of a parallelogram:Is it possible to have a regular polygon in which EACH EXTERIOR angle is 22°?How many sides does a regular polygon have if each interior angle measures 165°?