allerytan(A + B) equals:
AtanA + tanB
BtanA tanB
C(tanA + tanB)/(1 - tanA tanB)
D(tanA - tanB)/(1 + tanA tanB)
Answer & Solution
Correct answer: C. (tanA + tanB)/(1 - tanA tanB)
tan(A + B) = (tanA + tanB)/(1 - tanA tanB).
*Note: when tanA tanB = 1, denominator is 0 — that's when A + B = 90° + 180°k.*
Keep practising Unit 3A: Chain Rule and Composite Functions
Browse all Unit 3A: Chain Rule and Composite Functions questions for AP Calculus AB, or explore more Mathematics topics.
Related questions
In which quadrant is sin θ positive and cos θ negative?If tan θ + cot θ = 2, find sin 2θ:General solution of sin θ = sin α:In triangle with sides 7, 8, 9, find cos of the angle opposite to side 9 (use cosine rule)If sin θ = 12/13 (acute), find tan(θ/2):General solution of cos θ = 0:If sin θ + cos θ = 1, then sin θ × cos θ equals:In triangle ABC with sides a, b, c opposite to angles A, B, C: sine rule states: