If sin θ + cos θ = 1, then sin θ × cos θ equals:
A1/2
B1
C-1/2
D0
Answer & Solution
Correct answer: D. 0
Square both sides: (sin θ + cos θ)² = 1
→ sin²θ + cos²θ + 2 sinθ cosθ = 1
We have → 1 + 2 sinθ cosθ = 1 → sinθ cosθ.
So → 1 + 2 sinθ cosθ = 0.
Keep practising Unit 3A: Chain Rule and Composite Functions
Browse all Unit 3A: Chain Rule and Composite Functions questions for AP Calculus AB, or explore more Mathematics topics.
Related questions
In which quadrant is sin θ positive and cos θ negative?If tan θ + cot θ = 2, find sin 2θ:General solution of sin θ = sin α:In triangle with sides 7, 8, 9, find cos of the angle opposite to side 9 (use cosine rule)If sin θ = 12/13 (acute), find tan(θ/2):General solution of cos θ = 0:In triangle ABC with sides a, b, c opposite to angles A, B, C: sine rule states:sin(180° - θ) equals: