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For 0 ≤ θ < 2π, solutions of sin θ = 1/2:

A30° and 150°
B30°, 150°, 210°
C30° only
D60° only
Answer & Solution
Correct answer: A. 30° and 150°
sin θ = 1/2 in [0°, 360°): θ = 30° (Q1) and 180° - 30° = 150° (Q2). **General:** θ = 30° + 360°k OR θ = 150° + 360°k.
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