alleryThe sum of three consecutive multiples of 11 is 363. What is the largest of these three multiples?
A121
B132
C143
D154
Answer & Solution
Correct answer: B. 132
Let the three consecutive multiples of 11 be 11n, 11(n+1), 11(n+2).
Their sum is 11(3n + 3) = 33(n + 1).
Setting 33(n+1) = 363 gives n + 1 = 11, so n = 10. The three multiples are 110, 121, 132, and the largest is 132. Distractor 143 belongs to the next set (121+132+143 = 396), and 121 is the middle multiple, not the largest.
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