alleryThe product of the HCF and LCM of 6 and 20 is:
A26
B2
C120
D60
Answer & Solution
Correct answer: C. 120
HCF × LCM = 2 × 60 = 120 = 6 × 20.
Keep practising Unit 1B2: Algebraic Limits and Continuity
Browse all Unit 1B2: Algebraic Limits and Continuity questions for AP Calculus AB, or explore more Mathematics topics.
Related questions
The decimal expansion of $\dfrac{257}{2^3 \cdot 5^4}$ terminates after how many decimal plWhich of the following is an irrational number?The remainder when $2^{100}$ is divided by 7 isHow many positive integers less than 1000 are divisible by neither 2 nor 5?The HCF of two consecutive positive integers isIf $a = 2^3 \cdot 3^4 \cdot 5^2$ and $b = 2^4 \cdot 3^2 \cdot 7$, then $\dfrac{\text{LCM}(The smallest positive integer that is divisible by every integer from 1 to 10 isThe largest number that divides 245 and 1029, leaving remainders 5 and 5 respectively, is