Per NCERT Example 7.3, total gravitational PE of four equal masses at corners of a square of side l is approximately which?
A−5.41 G m² / l
B−G m² / l
C−4 G m² / l
D−10 G m² / l
Answer & Solution
Correct answer: A. −5.41 G m² / l
NCERT Ex 7.3: 4 pairs at distance l + 2 diagonal pairs at l√2 ⇒ U = −2Gm²/l(2 + 1/√2) = −5.41 Gm²/l.
Related questions
Tycho Brahe recorded his observations using:Kepler's three laws describe the motion of:The low escape speed of the moon explains why it has no:The moon's escape speed compared with the earth's is smaller by about:The escape speed for the moon works out to about:The law of periods uses which measurement of the ellipse?By the law of periods, the square of the period is proportional to:The law of areas explains why a planet moves slower when it is: