Home › NEET UG › physics › c11phy_grav_PE_escape › Per NCERT Example 7.3, total gravitational PE of…
Per NCERT Example 7.3, total gravitational PE of four equal masses at corners of a square of side l is approximately which?
A−5.41 G m² / l
B−G m² / l
C−4 G m² / l
D−10 G m² / l
Answer & Solution
Correct answer: A. −5.41 G m² / l
NCERT Ex 7.3: 4 pairs at distance l + 2 diagonal pairs at l√2 ⇒ U = −2Gm²/l(2 + 1/√2) = −5.41 Gm²/l.
Related questions
Per NCERT §7.7, the gravitational potential energy is a scalar quantity with dimensions whPer NCERT §7.7 (eqn 7.25), the gravitational POTENTIAL (per unit mass) at distance r from Per NCERT §7.8, the escape speed from a planet depends on which set of properties?Per NCERT §7.7, the gravitational PE of a particle DOUBLED in distance (r → 2r) from a masPer NCERT §7.8, why does the Moon NOT retain a significant atmosphere?Per NCERT §7.8, the escape speed from the Moon's surface is approximately which?Per NCERT §7.8, the numerical value of escape speed from the Earth's surface is approximatPer NCERT §7.8 eqn 7.32, the escape speed can also be written using g and R as which?