alleryFind the roots of $2x^2-5x+3=0$ by factorisation.
A$x=\frac{3}{2},\ 1$
B$x=\frac{5}{2},\ 3$
C$x=-\frac{3}{2},\ -1$
D$x=\frac{2}{3},\ 1$
Answer & Solution
Correct answer: A. $x=\frac{3}{2},\ 1$
Factorise $2x^2-5x+3$ by splitting the middle term: $2x^2-2x-3x+3=2x(x-1)-3(x-1)=(2x-3)(x-1)$.
So $(2x-3)(x-1)=0$, giving $2x-3=0$ or $x-1=0$.
**Hence the roots are $x=\frac{3}{2}$ and $x=1$.**
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