For any hyperbola, the eccentricity $e$ satisfies:

A$e = 0$

B$e < 1$

C$e = 1$

D$e > 1$

Answer & Solution

Correct answer: D. $e > 1$

Eccentricity scale across the conic family: | Conic | $e$ | |---|---| | Circle | $0$ | | Ellipse | $0 < e < 1$ | | Parabola | $e = 1$ | | **Hyperbola** | **$e > 1$** | For a hyperbola, $c^2 = a^2 + b^2 \Rightarrow c > a \Rightarrow e = c/a > 1$.

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