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Per NCERT §7.6 eqn 7.19, for depth d BELOW Earth's surface, the variation of g with d is which?
Ag(d) = g (1 + d/R_E)
Bg(d) = 0 always
Cg(d) = g (1 − 2d/R_E)
Dg(d) = g (1 − d/R_E)
Answer & Solution
Correct answer: D. g(d) = g (1 − d/R_E)
NCERT eqn 7.19: g(d) = g(1 − d/R_E). Only the inner sphere of radius (R−d) contributes; outer shell adds zero.
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