alleryIf the prime factorisations of two numbers are $2^3\times 3^2\times 5$ and $2^2\times 3\times 5^2$, then their HCF is
A$2^2\times 3\times 5$
B$2^3\times 3^2\times 5^2$
C$2\times 3^2\times 5$
D$2^2\times 5^2$
Answer & Solution
Correct answer: A. $2^2\times 3\times 5$
The HCF is formed by taking the common prime factors with the smallest powers.
For 2, the smaller power is 2
for 3, it is 1; for 5, it is 1. So HCF $=2^2\times 3\times 5$.
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