If $\alpha$ and $\beta$ are the zeroes of the quadratic polynomial $ax^2+bx+c$ with $a\neq 0$, then $\alpha+\beta$ equals
A$\dfrac{c}{a}$
B$\dfrac{b}{a}$
C$-\dfrac{b}{a}$
D$-\dfrac{c}{a}$
Answer & Solution
Correct answer: C. $-\dfrac{b}{a}$
For a quadratic polynomial $ax^2+bx+c$, the relation between zeroes and coefficients is $\alpha+\beta=-\dfrac{b}{a}$ and $\alpha\beta=\dfrac{c}{a}$.
**So the required value is $-\dfrac{b}{a}$.**
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