Start learning →

For the polynomial $p(x)=x^2-3x-4$, what is the value of $p(-1)$?

A$-8$
B$-2$
C$0$
D$2$
Answer & Solution
Correct answer: C. $0$
Substitute $x=-1$ into $p(x)$: $(-1)^2-3(-1)-4=1+3-4=0$. **Therefore, $p(-1)=0$.**
Practise this question with Quill — AP Calculus AB →

Keep practising Unit 1B2: Algebraic Limits and Continuity

Browse all Unit 1B2: Algebraic Limits and Continuity questions for AP Calculus AB, or explore more Mathematics topics.

Start a Unit 1B2: Algebraic Limits and Continuity lesson →