alleryThe zero of the linear polynomial $ax+b$ with $a\neq 0$ is
A$\dfrac{b}{a}$
B$-\dfrac{b}{a}$
C$-\dfrac{a}{b}$
D$\dfrac{a}{b}$
Answer & Solution
Correct answer: B. $-\dfrac{b}{a}$
If $k$ is a zero, then $ak+b=0$.
Solving gives $k=-\dfrac{b}{a}$.
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