Per NCERT Example 6.12, a flywheel of M=20 kg, R=0.2 m has I = MR²/2 = which?
A0.4 kg m²
B0.04 kg m²
C2.0 kg m²
D4.0 kg m²
Answer & Solution
Correct answer: A. 0.4 kg m²
NCERT Ex 6.12: I = (1/2)(20)(0.2)² = (1/2)(20)(0.04) = 0.4 kg m².
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