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Per NCERT §6.11 eqn 6.41, the rotational analogue of Newton's second law (F = m a) for rotation about a fixed axis is which?
Aτ = I ω
Bτ = I α
Cτ = (1/2) I α
Dτ = m a
Answer & Solution
Correct answer: B. τ = I α
NCERT eqn 6.41: net torque = moment of inertia × angular acceleration. Just substitute rotational analogues.
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