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As per your syllabus, eqn 6.25a, the ANGULAR MOMENTUM of a particle of momentum p at position r is which?
AL = r · p
BL = r × p
CL = p × r
DL = r + p
Answer & Solution
Correct answer: B. L = r × p
syllabus eqn 6.25a: L = r × p.
Magnitude L = r p sin θ; direction by right-hand rule.
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