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Per NCERT §6.7.1, the TORQUE (moment of force) on a particle at position r due to force F is which vector product?
Aτ = F × r
Bτ = r × F
Cτ = r · F
Dτ = r + F
Answer & Solution
Correct answer: B. τ = r × F
NCERT §6.7.1: τ = r × F. Vector quantity, perpendicular to plane of r and F. Magnitude τ = r F sin θ.
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