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As per your syllabus, eqn 6.19, the linear velocity of a particle of a rigid body rotating with angular velocity ω at position r is which?
Av = ω · r
Bv = ω + r
Cv = ω × r
Dv = ω / r
Answer & Solution
Correct answer: C. v = ω × r
syllabus eqn 6.19: v = ω × r.
Magnitude v = ω r sin θ
for circular motion v = ω r perpendicular to r.
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