Per NCERT §5.3, the WORK done by a constant force F on an object undergoing displacement d is which?
AW = F · d (= Fd cos θ)
BW = F + d (sum form)
CW = F d sin θ (incorrect)
DW = F / d (ratio form)
Answer & Solution
Correct answer: A. W = F · d (= Fd cos θ)
NCERT §5.3: W = F · d = F d cos θ. SI unit joule (J).
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