Per NCERT §5.3, the WORK done by a constant force F on an object undergoing displacement d is which?
AW = F · d (= Fd cos θ)
BW = F + d (sum form)
CW = F d sin θ (incorrect)
DW = F / d (ratio form)
Answer & Solution
Correct answer: A. W = F · d (= Fd cos θ)
NCERT §5.3: W = F · d = F d cos θ. SI unit joule (J).
Related questions
A crate dragged across a rough floor loses mechanical energy because friction is:Conservation of mechanical energy is the form the work-energy theorem takes when the forceCalculating work for a conservative force is easier than for a complicated path because itA force acting entirely perpendicular to an object's displacement does how much work?Mechanical energy transferred into or out of a system equals the work done by an external Winding up a toy or an old-fashioned watch stores energy by doing work against its:Which three energy examples are named together?The kinetic energy in the work-energy theorem is specifically the translational kinetic en