NEET · Bio · Principles of Inheritance · Hardy-Weinberg — Gap Fill

Exercise and reference answers

Missing parts

1. Answer

   0.4

   Choices

   1. 0.2
   2. 0.4
   3. 0.6
   4. 0.8

2. Answer

   0.48

   Choices

   1. 0.36
   2. 0.48
   3. 0.16
   4. 0.24

Complete the statement

If p = 0.6 then q = {0}. Heterozygous frequency 2pq = {1}.

Instructions

Hardy–Weinberg: p + q = 1; p² + 2pq + q² = 1.