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When the separation between the plates of an air parallel-plate capacitor is doubled (keeping plate area constant), the capacitance

Aremains unchanged
Bbecomes one-fourth
Cdoubles
Dhalves
Answer & Solution
Correct answer: D. halves
1. C = ε₀ A / d. 2. Doubling d gives C' = ε₀ A / (2d) = C/2. 3. So capacitance halves; the field also halves at fixed Q. _Source: syllabus Physics Part I, Ch 2 §2.12_
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