When the separation between the plates of an air parallel-plate capacitor is doubled (keeping plate area constant), the capacitance
Aremains unchanged
Bbecomes one-fourth
Cdoubles
Dhalves
Answer & Solution
Correct answer: D. halves
1. C = ε₀ A / d.
2. Doubling d gives C' = ε₀ A / (2d) = C/2.
3. So capacitance halves; the field also halves at fixed Q.
_Source: syllabus Physics Part I, Ch 2 §2.12_
Keep practising Electric Charges and Fields
Browse all Electric Charges and Fields questions for AP Intermediate 2nd Year, or explore more Physics topics.
Related questions
NEET · Physics · Electric Charges & Fields · Force on Dipole in FieldWhen light passes from one medium to another, which property remains **unchanged**?Electric potential is a:A convex lens forms a real image at $60$ cm on one side of an object placed $20$ cm in froTrue or false: electrostaticsThe work done in bringing a charge q from infinity to a point where the potential is V isA parallel-plate capacitor in vacuum has plate area A and separation d. Its capacitance isOn an equipotential surface, the work done in moving a test charge between any two points