Energy stored in a capacitor equals:
AQV
BCV
C2CV²
D½ CV²
Answer & Solution
Correct answer: D. ½ CV²
The energy stored in a capacitor is equal to the work done by a battery to move charge onto its plates.
1. **Relationship between Charge and Voltage**: The charge $Q$ on a capacitor is proportional to the potential difference $V$ across it, defined by $Q = CV$, where $C$ is the capacitance.
2. **Deriving Work (Energy)**: As we move a small increment of charge $dq$, the small amount of work done is $dW = V dq$. Since $V = q/C$ at any instant:
$$W = \int_{0}^{Q} \frac{q}{C} dq = \left[ \frac{q^2}{2C} \right]_{0}^{Q} = \frac{Q^2}{2C}$$
3. **Expressing in terms of C and V**: Substituting $Q = CV$ into the energy equation:
$$U = \frac{(CV)^2}{2C} = \frac{1}{2} CV^2$$
Therefore, the energy stored in a capacitor is $\frac{1}{2} CV^2$.
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