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The bond order in N₂, O₂ and O₂²⁻ (peroxide) are respectively:
A3, 1, 1
B2, 3, 1
C2, 2, 2
D3, 2, 1
Answer & Solution
Correct answer: D. 3, 2, 1
N₂: 10 b, 4 a → ½(6) = **3**. O₂: 10 b, 6 a → ½(4) = **2**. O₂²⁻ adds 2 electrons to π* MOs: 10 b, 8 a → ½(2) = **1**. Bond order falls as we go N₂ → O₂ → O₂²⁻ — and bond length correspondingly grows.
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