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According to MO theory, the bond order in a molecule is:

A½ (Nb + Na)
B(Nb + Na)/Nb
C(Nb − Na)
D½ (Nb − Na)
Answer & Solution
Correct answer: D. ½ (Nb − Na)
Bond order = **½ (N_b − N_a)**, where N_b/N_a are electrons in bonding/antibonding MOs. Positive bond order → stable zero or negative → unstable/non-existent.
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