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The hybridisation of S in SF₆ is:

Asp³
Bsp³d²
Csp³d³
Dsp³d
Answer & Solution
Correct answer: B. sp³d²
SF₆ is octahedral with 6 σ bonds. One s + three p + two d → **sp³d²**, giving six equivalent hybrids directed to the corners of a regular octahedron.
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