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In sp hybridisation, each hybrid orbital has the following s and p character:

A50% s, 50% p
B25% s, 75% p
C33% s, 67% p
D75% s, 25% p
Answer & Solution
Correct answer: A. 50% s, 50% p
sp: 1 s + 1 p → 2 equivalent hybrids each **50% s, 50% p**. **By contrast:** sp² is 33% s/67% p, sp³ is 25% s/75% p.
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