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According to VSEPR theory, the order of repulsion between electron pairs is:

AAll repulsions are equal
Bbp–bp > lp–bp > lp–lp
Clp–bp > lp–lp > bp–bp
Dlp–lp > lp–bp > bp–bp
Answer & Solution
Correct answer: D. lp–lp > lp–bp > bp–bp
Lone pairs occupy more space (only one nucleus attracts them) so repel more strongly: **lp–lp > lp–bp > bp–bp**. This explains compressed bond angles in NH₃ (107°) and H₂O (104.5°).
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