Per NCERT §1.3.3, the relative error in a measurement of 1.02 g with ±0.01 g uncertainty is approximately which percentage?
A≈ 0.01%
B≈ 10%
C≈ 1%
D≈ 0.1%
Answer & Solution
Correct answer: C. ≈ 1%
NCERT §1.3.3: (0.01 / 1.02) × 100 ≈ 1%. For 9.89 g with same absolute error: (0.01/9.89) ≈ 0.1%.
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