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The average O–H bond enthalpy in water is calculated from the two stepwise dissociation values (502 and 427 kJ mol⁻¹) as:
A427 kJ mol⁻¹
B929 kJ mol⁻¹
C502 kJ mol⁻¹
D464.5 kJ mol⁻¹
Answer & Solution
Correct answer: D. 464.5 kJ mol⁻¹
Average bond enthalpy = (502 + 427)/2 = **464.5 kJ mol⁻¹**. The two O–H bonds break with different ΔH because the chemical environment of the second bond differs from the first.
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