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Among H–H, F–F, Cl–Cl, Br–Br, I–I, the bond length is shortest for:
AF–F
BI–I
CCl–Cl
DH–H
Answer & Solution
Correct answer: D. H–H
From Table 4.3: H–H = 74 pm, F–F = 144, Cl–Cl = 199, Br–Br = 228, I–I = 267. **H–H is shortest** because H has the smallest covalent radius.
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