Start learning →

Among H–H, F–F, Cl–Cl, Br–Br, I–I, the bond length is shortest for:

AF–F
BI–I
CCl–Cl
DH–H
Answer & Solution
Correct answer: D. H–H
From Table 4.3: H–H = 74 pm, F–F = 144, Cl–Cl = 199, Br–Br = 228, I–I = 267. **H–H is shortest** because H has the smallest covalent radius.
Practise this question with Quill — NEET UG →

Keep practising Unit 2A: Chemical Bonding, Lewis Diagrams & Molecular Geometry

Browse all Unit 2A: Chemical Bonding, Lewis Diagrams & Molecular Geometry questions for NEET UG, or explore more Chemistry topics.

Start a Unit 2A: Chemical Bonding, Lewis Diagrams & Molecular Geometry lesson →
Related questions
The shape of $AsF_5$ according to VSEPR theory: ![](https://qallery.app/diagrams/v2_46c8bStability of the species $Li_2$, $Li_2^-$ and $Li_2^+$ increases in the order of:The order of increasing polarity in HCl, $\mathrm{CO}_{2}$ , $\mathrm{H}_{2}\mathrm{O}$ Isoelectronic species N₂, CO and NO⁺ all have a bond order of:Which of the following is an example of *intramolecular* hydrogen bonding?A hydrogen bond is formed when an H atom is covalently bonded to:The bond order in N₂, O₂ and O₂²⁻ (peroxide) are respectively:The paramagnetism of O₂ is explained by MO theory because the molecule has: