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For the NH₄⁺ ion, the total valence electrons available for writing the Lewis structure is:

A10
B12
C8
D9
Answer & Solution
Correct answer: C. 8
N (5) + 4 × H (1) = 9 from neutral atoms. **Subtract 1 for the +1 charge:** **9 − 1 = 8** electrons (i.e., 4 bonding pairs in the N–H bonds).
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