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In the Lewis structure of CO₃²⁻, the total number of valence electrons to be accounted for is:

A26
B24
C22
D28
Answer & Solution
Correct answer: B. 24
C contributes 4 + 3 × O contributes 6 = 22 from neutral atoms. Add 2 for the −2 charge: **22 + 2 = 24**.
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