Per NCERT §4.7.5, the BOND ORDER from MOT is defined as which expression?
Ab.o. = N_b × N_a
Bb.o. = N_b + N_a
Cb.o. = ½ × (N_b − N_a) — half the difference between bonding and antibonding electron counts
Db.o. = N_a − N_b
Answer & Solution
Correct answer: C. b.o. = ½ × (N_b − N_a) — half the difference between bonding and antibonding electron counts
Per NCERT §4.7.5, b.o. = ½(N_b − N_a). Positive → stable molecule; zero/negative → unstable.
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