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Factorise 4x²−(y−1)², distributing the minus signs in the factors correctly.

A(2x−y+1)(2x+y+1)
B(2x−y−1)(2x+y−1)
C(2x−y+1)(2x+y−1)
D(2x−y−1)(2x+y+1)
Answer & Solution
Correct answer: C. (2x−y+1)(2x+y−1)
The factors are 2x − (y − 1) and 2x + (y − 1), which become 2x − y + 1 and 2x + y − 1.
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