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x²+5x+k=(x+m)(x+n), with distinct positive integers m,n. What is the least possible k?

A6
B10
C4
D5
Answer & Solution
Correct answer: C. 4
The distinct positive pairs summing to 5 are 1 and 4, or 2 and 3; their products are 4 and 6, so the minimum is 4.
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