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HomeNEET UGphysicsc11instantvel › Per NCERT Example 2.1, an object's position is x…

Per NCERT Example 2.1, an object's position is x = a + bt² with a = 8.5 m, b = 2.5 m/s². What is its velocity at t = 0 s?

A0 m/s
B5.0 m/s
C8.5 m/s
D2.5 m/s
Answer & Solution
Correct answer: A. 0 m/s
Per NCERT Example 2.1, v = dx/dt = 2bt. At t=0, v = 0. The other options use wrong substitutions.
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