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A Wheatstone bridge with arms P, Q, R and S is balanced when
AP / S = Q / R
BP / Q = R / S
CP · Q = R · S
DP + Q = R + S
Answer & Solution
Correct answer: B. P / Q = R / S
At balance no current flows through the galvanometer, giving P/Q = R/S (equivalently PS = QR). The other relations are not the balance condition.
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