alleryIn the relation between current density j and electric field E inside an ohmic conductor,
Aj = E / σ
Bj = E²·σ
Cj is perpendicular to E
Dj = σ · E, where σ is conductivity
Answer & Solution
Correct answer: D. j = σ · E, where σ is conductivity
**Microscopic Ohm's law:** j = σE.
This is the local-field-form equivalent of V = IR for a uniform conductor.
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