A cell of emf ε = 6 V and internal resistance r = 1 Ω drives a current through an external resistance R = 5 Ω. The current in the circuit is
A0.6 A
B5.0 A
C1.0 A
D1.2 A
Answer & Solution
Correct answer: C. 1.0 A
We have I = ε / (R + r).
That is I = 6 / (5 + 1).
So I = 1 A.
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